0=-0.01x^2+0.6x+6.1

Solution for 0=-0.01x^2+0.6x+6.1 equation:

0=-0.01x^2+0.6x+6.1

We move all terms to the left:

0-(-0.01x^2+0.6x+6.1)=0

We add all the numbers together, and all the variables

-(-0.01x^2+0.6x+6.1)=0

We get rid of parentheses

0.01x^2-0.6x-6.1=0

a = 0.01; b = -0.6; c = -6.1;
Δ = b2-4ac
Δ = -0.62-4·0.01·(-6.1)
Δ = 0.604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{0.604}}{2*0.01}=\frac{0.6-\sqrt{0.604}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{0.604}}{2*0.01}=\frac{0.6+\sqrt{0.604}}{0.02}
$